...event with no chance of occurring) to...
...has a 1/2 chance of carrying the...
...and a 1/2 chance of carrying the...
...to determine the chance that two or...
...is 1/16 (1/4 chance for a YR...
...ovum and 1/4 chance for a YR...
...1/16 Therefore, the chance of at least...
...the rules of chance. Mendel’s laws of...
...attached earlobes. The chance of having a...
...1/4 ). The chance of having attached...
...have a 1/4 chance of having a...
...the disorder, 1/2 chance of a carrier,...
...has a 50% chance of inheriting the...
...have a 2/3 chance of being carriers...
...and a 1/3 chance of being homozygous...
...disease = 2/3 (chance that John is...
...carrier) x 2/3 (chance that Carol is...
...carrier) x 1/4 (chance that the offspring...
...are carriers. The chance that their next...
...to heredity. Because chance has no memory,...
...siblings. While the chance that John and...
...disorder is one chance in sixty four,...

...event with no chance of occurring) to...
...has a 1/2 chance of carrying the...
...and a 1/2 chance of carrying the...
...is 1/16 (1/4 chance for a YR...
...ovum × 1/4 chance for a YR...
...1/16. Therefore, the chance that a given...
...the rules of chance. Mendel’s laws of...
...has a 1/4 chance of inheriting the...
...disorder, a 1/2 chance of being a...
...and a 1/4 chance of being homozygous...
...has a 50% chance of inheriting the...
...have a 2/3 chance of being carriers...
...and a 1/3 chance of being homozygous...
...disease is 2/3 (chance that John is...
...carrier) × 2/3 (chance that Carol is...
...carrier) × 1/4 (chance that the offspring...
...that case, the chance that their next...
...to heredity. Because chance has no memory,...
...older siblings. The chance that John and...